Answer Key PSPCL LDC / UDC (General) Practice Set – 1

PSPCL LDC / UDC (General) Practice Set – 1

https://www.punjabexamportal.com/2015/12/09/pspcl-ldc-udcgeneral-practice-set/

Mock Test Solution UDC LDC PSPCL

Answer Key PSPCL LDC / UDC (General) Practice Set – 1
Q-1 – C Q-2 – D Q-3 – D Q-4 – B Q-5 – D Q-6 – C Q-7 – B Q-8 – B Q-9 – D Q-10 – D Q-11 – D Q-12 – B Q-13 – C Q-14 – B Q-15 – C Q-16 – B Q-17 – C Q-18 – C Q-19 – C Q-20 – C Q-21 – D Q-22 – B Q-23 – D Q-24 – B Q-25 – C	Q-26 – A Q-27 – D Q-28 – D Q-29 – B Q-30 – C Q-31 – B Q-32 – C Q-33 – A Q-34 – A Q-35 – C Q-36 – C Q-37 – A Q-38 – C Q-39 – C Q-40 – A Q-41 – C Q-42 – – Q-43 – B Q-44 – D Q-45 – D Q-46 – D Q-47 – A Q-48 – D Q-49 – C Q-50 – B	Q-51 – C Q-52 – C Q-53 – C Q-54 – C Q-55 – C Q-56 – C Q-57 – C Q-58 – B Q-59 – B Q-60 – B Q-61 – B Q-62 – A Q-63 – B Q-64 – D Q-65 – B Q-66 – A Q-67 – D Q-68 – D Q-69 – A Q-70 – D Q-71 – C Q-72 – C Q-73 – D Q-74 – B Q-75 – C	Q-76 – A Q-77 – C Q-78 – D Q-79 – A Q-80 – A Q-81 – D Q-82 – A Q-83 – * Q-84 – C Q-85 – B Q-86 – B Q-87 – B Q-88 – A Q-89 – C Q-90 – C Q-91 – A Q-92 – B Q-93 – B Q-94 – C Q-95 – A Q-96 – C Q-97 – A Q-98 – A Q-99 – C Q-100 – C

Solution-1
3*6*9 =162

Solution -2
a:b=2:3 b:c=5:8=(5*35:8*35)=3:245,
a:b:c=2:3:245=10:15: 24
b=98*1549=30

Solution -3
Let CP=100 & SP=175 also assume that he reduces x% amount to get no profit no loss.
X% of 175=100
X=400/7
That means he will offer=100-400/7=300/7=42.85%

Solution -4
Average after 11 innings should be 36
So, Required score = (11 * 36) – (10 * 32)
= 396 – 320 = 76

Solution -5
Let six years ago the age of Kunal and Sagar are 6x and 5x resp.
then,(6x+6)+4(5x+6)+4=11/10
10(6x+10)=11(5x+10)
5x=10
x=2
So Sagar age is (5x+6) = 16

Solution -6
‘m’ roots are 4 or -4

Solution -7
Date on 27th February 1603 was Thursday

Solution -8
Let 1 man’s 1 day work = x and 1 woman’s 1 days work = y.
Then, 4x + 6y = 1/8
and 3x+7y = 1/10
solving, we get y = 1/400 [means work done by a woman in 1 day] 10 women 1 day work = 10/400 = 1/40
10 women will finish the work in 40 days

Solution -9
Let the total time be x mins.
Part filled in first half means in x/2 = 1/40
Part filled in second half means in x/2 =
1/60+1/40=1/24
Total = x/2*1/40+x/2*1/24=1
x/2(1/40+1/24)=1
x/2*1/15=1
x=30mins

Solution -10
Difference between C.I and S.I for 2 years = 36.30
S.I. for one year = 330.
S.I. on Rs 330 for one year = 36.30
So R% = 36.30/330*100 = 11%

Solution -11
Speed=Distance/Time = 200/24
Convert km/h multiply by 18/5
200/24 * 18/5 = 30km/h

Solution -12 – Question incorrect
Correct Question is – If the length of a rectangle is increased by 30% and the width of the rectangle is decreased by 20%,then the area of the rectangle ________
Ans-B) Increases by 4%

Solution -13
Let Y/128 = 162/Y
Then x2 = 128 x 162
= 64 x 2 x 18 x 9
= 82 x 62 x 32
= 8 x 6 x 3
= 144.
x = 144 = 12

Solution -14
There are a total of 90 two digit numbers. Every third number will be divisible by ‘3’. Therefore, there are 30 of those numbers that are divisible by ‘3’.Of these 30 numbers, the numbers that are divisible by ‘5’ are those that are multiples of ’15’. i.e. numbers that are divisible by both ‘3’ and ‘5’. There are 6 such numbers — 15, 30, 45, 60, 75 and 90.
find out numbers that are divisible by ‘3’ and not by ‘5’, which will be 30 – 6 = 24.
24 out of the 90 numbers are divisible by ‘3’ and not by ‘5’.
The required probability is therefore, 24/90 = 4/15

Solution -15
Speed with current is 20,
speed of the man + It is speed of the current
Speed in still water = 20 – 3 = 17
Now speed against the current will be
speed of the man – speed of the current
= 17 – 3 = 14 kmph

Solution -16
P=(S.I.*100)/(R*T)
So by putting values from our question we can get the answer
P=(4016.25*100)/(9*5)=8925

Solution -17
Given – 30 liters mixture in ratio of milk and water 7:3
means milk is 21 literss and water is 9 liters
because resultant water in mixture 40%, means milk is 60%
new ratio is 60:40 = 3:2
21/(9 + x)=3/2
x=5

Solution -18
As Shyam is helped by Ram and Singhal every third day, Shyam works for 3 days while Ram and Singhal work for 1 day in every 3 days.
Therefore, the amount of work done in 3 days by Shyam, Ram and Singhal:
= 3/20+1/30+1/60
=1/5 of the job.
Hence, it will take them 5 times the amount of time = 3×5 = 15 days.

Solution -19
The total time of journey = 5 hours.
Let ‘x’ hours be the time that I traveled at 40 kmph
Therefore, 5 – x hours would be time that I traveled at 60 kmph.
Hence, I would have covered x*40 + (5 – x)60 kms in the 5 hours = 240 kms.
Solving, for x in the equation 40x + (5 – x)*60 = 240, we get
40x + 300 – 60x = 240
20x = 60 or x = 3 hours.

Solution -20
Let S be the selling price of 1 article.
Therefore, the selling price of 100 articles = 100 S.P. –(1)
The profit earned by selling these 100 articles = selling price of 75 articles = 75 S.P — (2)
We know that Selling Price (S.P.) = Cost Price (C.P) + Profit — (3)
Selling price of 100 articles = 100 S.P and Profit = 75 S.P from (1) and (2). Substituting this in eqn (3), we get
100 S.P = C.P + 75 S. Hence, C.P = 100 S.P – 75 S.P = 25 S.P
Profit % = (Profit/C.P)*100 = (75/25)*100 =300

Solution -21
A:B:C = 35000:45000:55000
= 7:9:11
to get the share, first make total of above ratio.
then get each share.
D) Rs. 10500, Rs. 13500, Rs. 16500

Solution -22
Let the present age of Baskar be ‘b’ and that of Rajesh be ‘r’.
So, r = b – 10 …. eqn (1).
10 years back Rajesh was (r – 10) years old. 10 years back Baskar was (b – 10) years old.
The question states that 10 years back Rajesh was two thirds as old as Baskar was.
i.e., (r – 10) = (2/3)*(b – 10) …. eqn (2).
Cross multiplying, we get 3(r – 10) = 2(b – 10)
or 3r – 30 = 2b – 20 …. eqn (2)
From eqn (1) we can substitute r as (b – 10) in eqn (2)
So, 3(b – 10) – 30 = 2b – 20
or 3b – 30 – 30 = 2b – 20
or b = 40.
The present age of Baskar is 40 years.

Solution -23
1/4th of a number is 17
means actual number is = 17*4 = 68
45% of 68 = 68*45/100 = 30.6

Solution -24
Distance covered = 120+120 = 240 m
Time = 12 s
Let the speed of each train = x.
Then relative velocity = x+x = 2x
2x = distance/time = 240/12 = 20 m/s
Speed of each train = x = 20/2 = 10 m/s
= 10*18/5 km/hr = 36 km/hr

Solution-25
All are prefect square except 20
So ans is -20

Solution -26
Ans is A)©$37 (In question paper option typed ‘©S37’ by mistake)

Solution -27
TOUR – 1234
CLEAR – 56784
SPARE – 90847
From above three given statement
we can find code of SCULPTURE – 953601347
5th digit is – 0

Solution -28 (incorrect Option) (Option D is 4 instead of 24)
in first column , 13+7*2 = 27
2nd column = 54+45*2 = 144
let missing number is x
No 3rd column is x+32*2 =68
x = 4

Solution -29
6*2 + 1 =13
13*2 + 2 = 28
28*2 + 3 = 59
59*2 + 4 = 122

Solution -30
South-East becomes North – move on right side ‘South-East’->’East’->’Noth-East’->’North’
South becomes North-East – move on right side ‘South’->’South-East’->’East’->’Noth-East’
Same way
West become ‘South-East’ – move on right side ‘West’->’South-West’->’South’->’South-East’

Solution -31
From figure 1st 2nd and 4th we conclude that 6,4,1 and 2 dots appear adjacent to 3 dots.
Clearly there will be five dots on the face opposite the face with 3 dots

Solution -32
The above three numbers are multiples of the numbwer at the bottom
Clearly 45,18,27 are all multiple of 9, So missing number is 9

Solution -33
The middle letters are static, so concentrate on the first and third letters.
The series involves an alphabetical order with a reversal of the letters.
The first letters are in alphabetical order: F, G, H, I , J.
The second and fourth segments are reversals of the first and third segments.
The missing segment begins with a new letter.

Solution -34
Clearly, 1st, 8th, 15th, 22nd, and 29th October are Sundays.
So, 31st October is Tuesday.
So 1st November will be Wednesday.

Solution -35
Clearly, Number students behind the nitin in rank = (49 – 18) = 31
Nitin is 32nd from the last

Solution -36
Here Physics, Chemistry, Zoology deals with science but Geography is not.

Solution -37
The number of doctors who are neither artists nor players is 17.

Solution -38
The number of doctors who are both players and artists is 3.

Solution -39
The number of artists who are players is 22 + 3 = 25.

Solution -40
The number of players who are neither artists nor doctors is 25.

Solution -41
The number of artists who are neither players nor doctors is 30.

Solution -42 –

Solution -43
Mirror image of 8:35 is 3:25

Solution -44
Mirror image is 4th

Question number 45 to 47

Solution -45
The code for ‘money’ is ‘la’.

Solution -46
The code for ‘supply’ is either ‘mo’ or ‘ta’

Solution -47
demand – ‘mo’ or ‘ta’
only – ‘ne’ or ‘ki’
The code for ‘more’ may be ‘xi’

Solution -48
Answer is ‘aacb’
Now complete series is [abc ab bca bc cab ca abc ab]

Solution -49
3rd figure is right asnwer

Solution -50
The word ‘OPTICAL’ contains 7 different letters.
When the vowels OIA are always together, they can be supposed to form one letter.
Then, we have to arrange the letters PTCL (OIA).
Now, 5 letters can be arranged in 5! = 120 ways.
The vowels (OIA) can be arranged among themselves in 3! = 6 ways.
Required number of ways = (120 x 6) = 720.